For problems of this type, you need to first graph, and then shade the solution region using test points.
While you graph, make sure that you have a dotted line, since this inequality has the symbol ">" and not "≥".
For the second equation,
You can now place the y intercept, which is
You can then connect these dots using a complete line, not a dotted one, since the symbol used in this case is
As for the shading, usually for quadratic inequalities I would select test points and for linear inequalities I would shade through logical induction. In
Let Test Point #1 be (0, 0)
So, we shade inside the parabola.
Once this is done, the solution to the inequality is the region where the two shaded areas overlap.
Here is what you should have in the way of graphing, except your graph should have the parabola as a dotted line (my program can for some reason not draw this properly).
As for points of intersection, I think the graph says it all. A few examples are
Hopefully this helps!
Another way, algebraically:
The roots of
Given a restriction on
Note that the restrictions on the
But points such as