Question #04a12

1 Answer
Aug 28, 2016

Assuming the situation is that where a piece of ice is dropped in a glass of water at room temperature which is much greater than #4^@C#

To explain let us consider

#M_i->"Mass of the piece of ice floated"#

#d_w="Density of water"#

Volume of water obtained on melting ice#V_w=M_i/d_w#

As the ice is floating then by the condition of floatation,

The mass of water displced by floating ice is same as the mass of ice #M_i#
So the volume of this displaced water#=V_d=M_i/d_w#

Since #V_w=V_d#,we can easily say the water level will remain at the same position as before the melting of floated ice in water.