Substitute each value of #x# into the equation and solve for #y#. You will see that the values for #x# and #y# on the table will be determined by using the equation #y=2x+3#.

#(color(red)x,color(blue)y)#

#color(blue)y=2color(red)x+3#

#(color(red)1,color(blue)5)rArr#

#color(blue)y=2*color(red)1 + 3=2+3=color(blue)5#

#(color(red)2,color(blue)7)rArr#

#color(blue)y=2*color(red)2+3=4+3=color(blue)7#

#(color(red)3,color(blue)9)rrArr#

#color(blue)y=2*color(red)3 + 3=6+3=color(blue)9#

#(color(red)4,color(blue)11)rArr#

#color(blue)y=2*color(red)4+3=8+3=color(blue)11#