# Question #e07a4

Aug 31, 2016

$\left(f + g\right) \left(- 2\right) = 24$

#### Explanation:

Using the notation that for given functions $f$ and $g$ that $\left(f + g\right) \left(x\right) = f \left(x\right) + g \left(x\right)$, we have

$\left(f + g\right) \left(- 2\right) = f \left(- 2\right) + g \left(- 2\right)$

$= \left(2 {\left(- 2\right)}^{2} - 7 \left(- 2\right) + 6\right) + \left(\left(- 2\right) - 2\right)$

$= \left(8 + 14 + 6\right) + \left(- 4\right)$

$= 30 - 4$

$= 24$

Note that we can also solve generally for $\left(f + g\right) \left(x\right)$ and then plug $- 2$ in:

$\left(f + g\right) \left(x\right) = f \left(x\right) + g \left(x\right)$

$= \left(2 {x}^{2} - 7 x + 6\right) + \left(x - 2\right)$

$= 2 {x}^{2} - 6 x + 4$

Plugging in $- 2$ leads to the same result:

$2 {\left(- 2\right)}^{2} - 6 \left(- 2\right) + 4 = 8 + 12 + 4 = 24$