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Answer 1 · 2016-08-31T17:24:17

#(f+g)(-2)=24#

Using the notation that for given functions #f# and #g# that #(f+g)(x) = f(x) + g(x)#, we have

#(f+g)(-2) = f(-2)+g(-2)#

#=(2(-2)^2-7(-2)+6) + ((-2)-2)#

#=(8+14+6)+(-4)#

#=30-4#

#=24#

Note that we can also solve generally for #(f+g)(x)# and then plug #-2# in:

#(f+g)(x) = f(x) + g(x)#

#= (2x^2-7x+6) + (x-2)#

#=2x^2-6x+4#

Plugging in #-2# leads to the same result:

#2(-2)^2-6(-2)+4 = 8 + 12 + 4 = 24#