# How would we represent the reduction of MnO_2 to give Mn^(2+) in acidic conditions?

Sep 1, 2016

Manganese is reduced from $M {n}^{I V +}$ to $M {n}^{I I +}$,....

#### Explanation:

And of course, for every reduction there is a corresponding oxidation: here, chloride ion is oxidized to zerovalent chlorine gas.

The overall (balanced) redox equation is:

$M n {O}_{2} \left(s\right) + 4 H C l \left(a q\right) \rightarrow M n C {l}_{2} \left(s\right) + C {l}_{2} \left(g\right) + 2 {H}_{2} O \left(l\right)$

Is that balanced? Do not trust my arithmetic!