# Question #f5b12

Sep 1, 2016

$\frac{1}{3}$

#### Explanation:

There are 30 tickets in the first box and 28 in the second.

P(More than 21, More than 20) = $\frac{10}{30} \times \frac{28}{28} = \frac{1}{3}$

P(Less than 3, Less than 3) = $\frac{2}{30} \times \frac{0}{28} = 0$

P(both more than 20 OR less than 3) = $\frac{1}{3} + 0 = \frac{1}{3}$