# Question #34559

Oct 9, 2016

-.56g or the car is decelerating at .56g.

#### Explanation:

Acceleration is equal to the slope of a velocity vs. time graph or (change in velocity/change in time)

If you are only looking for the acceleration from t=5 to t=9:
1. Change in velocity: $22 \frac{m}{s}$
2. Change in time: 4s
3. (Change in velocity)/(Change in time)=$\frac{5.5 m}{s} ^ 2$
4. $\frac{5.5 \frac{m}{s} ^ 2}{9.80 \frac{m}{s} ^ 2} = .56 g$ (negative)

If you are looking for the average acceleration between t=0 to t=9:
1. Change in velocity: $22 \frac{m}{s}$
2. Change in time: 9s
3. (Change in velocity)/(Change in time)=$\frac{2.44 m}{s} ^ 2$
4. $\frac{2.44 \frac{m}{s} ^ 2}{9.80 \frac{m}{s} ^ 2}$=.25g (negative)