Question #34559

1 Answer
Oct 9, 2016

Answer:

-.56g or the car is decelerating at .56g.

Explanation:

Acceleration is equal to the slope of a velocity vs. time graph or (change in velocity/change in time)

If you are only looking for the acceleration from t=5 to t=9:
1. Change in velocity: #22m/s#
2. Change in time: 4s
3. (Change in velocity)/(Change in time)=#(5.5m)/s^2#
4. #(5.5m/s^2)/(9.80m/s^2)=.56g# (negative)

If you are looking for the average acceleration between t=0 to t=9:
1. Change in velocity: #22m/s#
2. Change in time: 9s
3. (Change in velocity)/(Change in time)=#(2.44m)/s^2#
4. #(2.44m/s^2)/(9.80m/s^2)#=.25g (negative)