Question

Question #34559

Answer 1

-.56g or the car is decelerating at .56g.

Explanation:

Acceleration is equal to the slope of a velocity vs. time graph or (change in velocity/change in time)

If you are only looking for the acceleration from t=5 to t=9:
1. Change in velocity: `22m/s`
2. Change in time: 4s
3. (Change in velocity)/(Change in time)=`(5.5m)/s^2`
4. `(5.5m/s^2)/(9.80m/s^2)=.56g` (negative)

If you are looking for the average acceleration between t=0 to t=9:
1. Change in velocity: `22m/s`
2. Change in time: 9s
3. (Change in velocity)/(Change in time)=`(2.44m)/s^2`
4. `(2.44m/s^2)/(9.80m/s^2)`=.25g (negative)