Question

Question #ff82b

Answer 1

`sintheta=-3/5,180 < theta <270`

The angle `theta` lies in the third quadrant.

Where

`costheta,sectheta and csctheta-> -ve`

`and tantheta and cottheta->+ve`

So

`csctheta=-5/3`
`costheta=-sqrt(1-sin^2theta)=sqrt(1-9/25)=-4/5`

`sectheta=-5/4`

`tantheta=sintheta/costheta=(-3/5)/(-4/5)=3/4`

`cottheta=4/3`