What is the electron configuration of copper? Why is it NOT #[Ar]3d^9 4s^2#?

1 Answer
Jul 25, 2017

It is #[Ar] 3d^10 4s^1#, rather than an expected #[Ar] 3d^9 4s^2#.


And this "anomaly" arises from not recognizing the difference in energy between the #3d# and #4s# orbitals. For copper, the #3d# are about #"5.05 eV"#, or about #"487.25 kJ/mol"# LOWER in energy than the #4s# (which is a huge difference!).

Hence, it should be clear that the #3d# orbitals are filled for copper BEFORE filling the #4s#.

That gives rise to the so-called "anomalous configuration", which is in fact the correct, normal one when one properly follows the Aufbau principle (lowest energy fills first!):

#barul(|stackrel(" ")(" "[Ar] 3d^10 4s^1" ")|)#

The reason why one would get #3d^9 4s^2# is if one filled the #4s# first and the #3d# second, with the total of #11# electrons in the #3d# and #4s# orbitals.

http://ptable.com/

But that wouldn't make sense, since the #3d# orbital is not higher in energy, but lower.

(It is just a poor interpretation of the Aufbau principle by inference off of pre-transition metals, and follows from habitually using the periodic table #s# and #d# blocks from left to right.)