No -- all you have to do is graph the function on your calculator, then examine the point at x=-3x=−3, which is (-3,0)(−3,0).
Note that if the limit were, say, lim_(wrarr2)(w^2-4)/(w-2), you would evaluate this as lim_(wrarr2)(w+2)=4. When graphically supporting this, you would see that the function approaches the point (2,4) from both sides, even though the function is undefined at w=2.
And, yes, even though this is a function f(y), it would be input in your calculator with all x variables. A function can have any variable, but x for the horizontal (input) axis and y for the vertical (output) axis are standard.