Question

Question #b29dc

Answer 1

`cot(1395^@)=-1`.

Explanation:

`cot(1395^@)=cot(1440^@-45^@)=cot{4(360^@)-45^@}`.

Therefore, `1395^@` lies in the `IV^(th)` Quadrant, in which, `cos`

& `sec` are `+ve`, so, cot is `-ve`, and,

`cot(1395^@)=cot{4(360^@)-45^@}=-cot45^@=-1`.