# Is the reaction between hydrogen sulfide and sodium hydroxide a redox process?

Sep 11, 2016

$\text{LEO SAYS GER}$. $\text{Loss of electrons: OXIDATION}$.
$\text{Gain of electrons: REDUCTION}$
For ${H}_{2} S \left(a q\right) + 2 N a O H \rightarrow N {a}_{2} S \left(a q\right) + 2 {H}_{2} O \left(l\right)$, there is not electron transfer. This is an acid base reaction, not a redox process.
Sulfur is ${S}^{- I I}$ in both acid and in the salt. Hydrogen ion is not reduced to dihydrogen gas. I think you should review the assignment of oxidation numbers.