# Question 8380b

Sep 13, 2016

${\text{1.07 g/cm}}^{3}$

#### Explanation:

Here's a quick way of figuring out the density of the saline solution.

Notice that the problem provides you with the density of pure water at ${4}^{\circ} \text{C}$. Use this to find the volume of pure water that has a mass of $\text{11.3 g}$ at that temperature

11.3 color(red)(cancel(color(black)("g"))) * "1 cm"^3/(1.00color(red)(cancel(color(black)("g")))) = "11.3 cm"^3

Since you know that an equal volume of saline solution has a mass of $\text{12.g}$ at ${4}^{\circ} \text{C}$, you can say that its density, ${\rho}_{\text{sal}}$, will be equal to

rho_"sal" = "12.1 g"/"11.3 cm"^3 = color(green)(bar(ul(|color(white)(a/a)color(black)("1.07 g/cm"^3)color(white)(a/a)|)))#

The answer is rounded to three sig figs.