# Question #f6e45

$\frac{1}{4}$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{1}{2} {\left(x + 1\right)}^{- \frac{1}{2}}$
At x=3, it would be $\frac{1}{2} {\left(4\right)}^{- \frac{1}{2}}$ = $\frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}$