Question #e4cf1

1 Answer
Jun 19, 2017

Answer:

I tried this:

Explanation:

Your function is the natural logarithm or logarithm in base #e#.
This function can accept all Real values bigger than zero; because the definition of log:
#log_bx=y#
#x=b^y#
zero cannot be found in the sense that:
#ln0=???# no real number can be found to fulfill the requirement that #e^y=0#. For sure #x# cannot be negative because it is not possible to find an exponent that makes a number negative.

So the domain will be:

#0 < x < +oo#

The range will be all the Real number so that #y# will be:

#-oo < y < +oo#

Graphically we see this as:
graph{ln(x) [-12.66, 12.65, -6.33, 6.33]}