# Question e4cf1

Jun 19, 2017

I tried this:

#### Explanation:

Your function is the natural logarithm or logarithm in base $e$.
This function can accept all Real values bigger than zero; because the definition of log:
${\log}_{b} x = y$
$x = {b}^{y}$
zero cannot be found in the sense that:
ln0=???# no real number can be found to fulfill the requirement that ${e}^{y} = 0$. For sure $x$ cannot be negative because it is not possible to find an exponent that makes a number negative.

So the domain will be:

$0 < x < + \infty$

The range will be all the Real number so that $y$ will be:

$- \infty < y < + \infty$

Graphically we see this as:
graph{ln(x) [-12.66, 12.65, -6.33, 6.33]}