What mass of benzene is required for a combustion reaction that yields a mass of #42*g# with respect to carbon dioxide?

1 Answer
Sep 25, 2016

Answer:

Approx. #13*g# benzene were required.

Explanation:

Given the stoichiometric rxn:

#C_6H_6(l) + 15/2O_2(g) rarr 6CO_2(g) + 3H_2O(l)#

As a product we have #(42.0*g)/(44.01*g*mol^-1)# #~=# #1*mol" carbon dioxide"# gas.

And thus approx. #1/6*mol# benzene were required for the combustion, #=# #1/6molxx78.0*g*mol^-1# #=# #??*g#.

You can of course make a better estimate than I did.