Question #ed224

1 Answer
Jan 6, 2017

Answer:

Option -A

Explanation:

given

Considering the equilibrium of forces acting on the beam we can say that the moment of the applied upward force #F=5N# acting at P about the pivot O will be equal to the moment of the weight #W# about O, but they will be oppositely directed.

So

#OQxxW=OPxxF#

#=>W=(OPxxF)/(OQ)=(OPxxF)/(OP+PQ)=(2xx5)/((2+3))=2N#