Question

Question #ed224

Answer 1

Option -A

Explanation:

Considering the equilibrium of forces acting on the beam we can say that the moment of the applied upward force `F=5N` acting at P about the pivot O will be equal to the moment of the weight `W` about O, but they will be oppositely directed.

So

`OQxxW=OPxxF`

`=>W=(OPxxF)/(OQ)=(OPxxF)/(OP+PQ)=(2xx5)/((2+3))=2N`