Question

Question #08218

Answer 1

Number of Isomers of the compound = `2^n`
where n = no. of chiral carbon atoms

Explanation:

eg: Glucose

Glucose has different ends with C at both ends, one carbon with aldehyde group and other carbon with alcohol group.

In this case
Number of Isomers of the compound = `2^n`
where n = no. of chiral carbon atoms = 4
No. of Isomer =`2^4` = `16`
Hence glucose has `16` structural isomers.