Question #9ee2e

Sep 29, 2016

We know molar mass of Hydrogen is $= 2 \frac{g}{\text{mol}}$

The amount of hydrogen given is $= 4.47 \times {10}^{-} 4 g = \frac{4.47 \times {10}^{-} 4 g}{2 \frac{g}{\text{mol}}}$
$= 2.235 \times {10}^{-} 4 m o l$

The equation of the reaction

${N}_{2} + 3 {H}_{2} \to 2 N {H}_{3}$

As per this equation

3 moles ${H}_{2}$ produces 2 moles $N {H}_{3}$

So
$2.235 \times {10}^{-} 4 m o l$ H_2 will

produce $\frac{2}{3} \times 2.235 \times {10}^{-} 4 m o l N {H}_{3}$

$= \frac{2}{3} \times 2.235 \times {10}^{-} 4 \times 6.023 \times {10}^{23} \text{ molecules } N {H}_{3}$

$\approx 8.97 \times {10}^{23} \text{ molecules } N {H}_{3}$