# Question #2e9b5

Sep 27, 2016

$7.833 \frac{g}{c {m}^{3}}$

#### Explanation:

As you would know, the density of an object is its mass per unit volume, and can be calculated as follows:

Density, $D$ = Total Mass of the Object, $m$ / Total Volume of the Object, $V$

Mass of the iron block, $m = 94 g$

Volume of the iron block, $V = 2 c m \cdot 3 c m \cdot 2 c m = 12 c {m}^{3}$

Density, $D = \frac{m}{V}$

$= \frac{94 g}{12 c {m}^{3}}$

$= 7.833 \frac{g}{c {m}^{3}}$