# Question #e1818

Oct 2, 2016

Summing up the number of $\sigma$-bond formed by the desired atom (here N) and the number of lone pair on it we can easily know the hybridization of it.

$\text{If the sum is 2 "->"hybridization} - s p$

$\text{If the sum is 3 "->"hybridization} - s {p}^{2}$

$\text{If the sum is 4 "->"hybridization} - s {p}^{3}$

$\text{If the sum is 5 "->"hybridization} - s {p}^{3} d$

$\text{If the sum is 6 "->"hybridization} - s {p}^{3} {d}^{2}$

Inspecting the Lewis structure of $H - C \equiv N :$ we see that N-atom has one $\sigma$-bond and one lone pair so sum is 2.
Hence the hybridization is sp.