Question #39e4b

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Answer 1 · 2016-10-03T01:41:52

#c->"Current strength"=2.5A#

#t->"Time for current"=1hr20min#
#=(3600+1200)s=4800s#

#"Quantity of eletricity passed"#

#=cxxt=2.5xx4800C=12000/96500F#

The reaction at anode

#2OH^(-)-2e->H_2O+1/2O_2#

This equation reveals that 2F of electricity produces 0.5 moles #O_2#

So #12000/96500F# electricity will produce

#1/2xx0.5xx12000/96500" moles"O_2#

Given molar volume at r.t.p is #24dm^3#.
The volume of oxygen produced at anode will be

#=1/2xx0.5xx12000/96500xx24dm^3#

#=0.746dm^3#