Solve linear system of equations ?

1 Answer
Sep 30, 2016

Answer:

#x_1=0,x_2=-1,x_3=-1,x_4=2#

Explanation:

Supposing that my understanding of the problem is the right one,

Calling

#M_1 = ((1, 1, 1, 1),(2, -1, -1, -1))# and #b_1 = ((0),(0))#

#M_2 = ((1, 1, 2, 2),(1, 2, 2, 1))# and #b_2=((7),(4))#

and

#w = (1,1,1,1)^T#
#V = (x_1,x_2,x_3,x_4)^T# we have

#S_1->M_1 cdot X = b_1# and
#S_2->M_2 cdot (X+w)=b_2#

Solving the system

#((M_1),(M_2))cdotX = ((b_1),(b_2-M_2cdot w))# we obtain

#x_1=0,x_2=-1,x_3=-1,x_4=2#