# Question #a3830

Oct 3, 2016

Equation of the Reaction

$L {i}_{2} S + C o {\left(N {O}_{3}\right)}_{2} \to C o S + 2 L i N {O}_{3}$

This equation reveals that 1 mol $L {i}_{2} S$ is required to react completely with 1 mol $C o {\left(N {O}_{3}\right)}_{2}$

Let V L be the volume of0.160 M $L {i}_{2} S$ solution required to react completely with 125ml or 0.125L 0.160M $C o {\left(N {O}_{3}\right)}_{2}$ solution.

$L {i}_{2} S$ contains $V \times 0.160 m o l$ solute

$C o {\left(N {O}_{3}\right)}_{2}$ solution contains $0.125 \times 0.160 m o l$ solute

$V \times 0.160 = 0.125 \times 0.160$

$\therefore V = 0.125 L = 125 m L$