# Question #8fcbb

Nov 7, 2016

0.00278 moles of oxygen atoms are present in 0.05g of water.

#### Explanation:

Let us consider an equation:
$2 {H}_{2} O \to 2 {H}_{2} + {O}_{2.}$

So, 2 moles of water molecule consists of 1 mole of oxygen molecule.
In other words, 36 grams of water consists 2 moles of oxygen atoms .

$\therefore$0.05 grams of water consists of $= \frac{2}{36} \times 0.05$ moles of oxygen atoms , i.e. 0.00278 moles of oxygen atoms.