Question #4112a

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Answer 1 · 2016-10-07T05:45:24

No solution

#{(2x-3y = 6), (6x=9y+9):}#

Dividing the second equation by #3#, we get

#(6x)/3 = (9y)/3+9/3#

#=> 2x = 3y + 3#

Substituting our new value for #2x# into the first equation, we get

#(3y+3) - 3y = 6#

#=> 3 = 6#

As this is a contradiction, no #(x, y)# pair satisfies both given equations. The system has no solution.