What is pH of a 0.002molL1 solution of HCl(aq)?

1 Answer
Oct 6, 2016

pH=log10[H3O+]

Explanation:

[H3O+] = 102L×0.1molL1500mL×103LmL1

= 2.0×103molL1

And log10(2.0×103) = (2.70)=2.70