Question

Question #4b882

Answer 1

I found:
`l_("Earth")=1m`
`l_("Moon")=20cm`

Explanation:

Here you could use the fact that the period `T` of a pendulum depends upon its length `l` and the acceleration of gravity `g` as:
`T=2pisqrt(l/g)`

and rearranging:

`l=(T/(2pi))^2*g`

1) on Earth `g=9.8m/s^2`
so you get:
`l_("Earth")=(2/(2pi))^2*9.8=0.99~~1m`

2) On the Moon we have `g_("Moon")=1.6 m/s^2` (from literature) and so:
`l_("Moon")=(2/(2pi))^2*1.6=0.16~~0.2m=20cm`