Question #52822

1 Answer
Oct 17, 2016

Let the mass of CO was #wg#

Now

#M->"Molar mass of "CO =28" g/mol"#

#V->"Initial Vol of CO"=0.52L#

#P->"Initial Pressure of CO"=1.5atm#

#V->"Initial Temp of CO"=331K#

#R->"Universal gas constant"=0.082LatmK^-1mol^-1#

By Ideal gas law

#PV=w/MRT#

#=>w=(PVM)/(RT)=(1.5xx0.52xx28)/(0.082xx331)=0.805g#

In certain adjusted pressure and temperature when its volume becomes 2.7L ,its density will be
#D="mass"/"volume"=0.805/2.7g/L~~0.3g/L#