# What is the net ionic equation for the reaction between hydroiodic acid, and potassium hydroxide?

Oct 13, 2016

This is simply: $H {O}^{-} + {H}^{+} \rightarrow {H}_{2} O \left(a q\right)$ OR $H {O}^{-} + {H}_{3} {O}^{+} \rightarrow 2 {H}_{2} O \left(a q\right)$

#### Explanation:

And the complete equation:

$N a O H \left(a q\right) + H I \left(a q\right) \rightarrow N a I \left(a q\right) + {H}_{2} O \left(l\right)$

So this is an acid base neutralization. Sodium and iodide ions are along for the ride, and remain solvated aqua ions in aqueous solution: i.e. we write $N a I \left(a q\right)$ or $N {a}^{+}$ and ${I}^{-}$; at a molecular level $N {a}^{+} \left(a q\right)$ $=$ $N a {\left(O {H}_{2}\right)}_{6}^{+}$ for instance.

Bond making is conceived to occur between the hydronium ion, ${H}_{3} {O}^{+}$, and the hydroxide ion, $H {O}^{-}$ to form 2 equiv of water:

$H {O}^{-} + {H}_{3} {O}^{+} \rightarrow 2 {H}_{2} O$

Mass is balanced, and charge is balanced in all these equations (I think so anyway), so these are reasonable equations.