# What mass of sodium chloride is present in a 250*mL volume of 5.0*mol*L^-1 NaCl(aq)?

Oct 15, 2016

$\text{Mass of NaCl} \cong 75 \cdot g$

#### Explanation:

We use the relationship:

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$

We know $\text{Concentration}$ and $\text{Volume}$, and thus

$\text{Moles of solute}$ $=$ $\text{Concentration"xx"Volume of solution}$

$=$ $5.0 \cdot m o l \cdot \cancel{{L}^{-} 1} \times 250 \cdot \cancel{m L} \times {10}^{-} 3 \cdot \cancel{L} \cdot \cancel{m {L}^{-} 1}$

$=$ $1.25 \cdot m o l$

And a $1.25 \cdot m o l$ quantity of sodium chloride has a mass of $1.25 \cdot \cancel{m o l} \times 58.44 \cdot g \cdot \cancel{m o {l}^{-} 1}$ $=$ ??*g