What mass of sodium chloride is present in a #250*mL# volume of #5.0*mol*L^-1# #NaCl(aq)#?

1 Answer
Oct 15, 2016

Answer:

#"Mass of NaCl"~=75*g#

Explanation:

We use the relationship:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

We know #"Concentration"# and #"Volume"#, and thus

#"Moles of solute"# #=# #"Concentration"xx"Volume of solution"#

#=# #5.0*mol*cancel(L^-1)xx250*cancel(mL)xx10^-3*cancelL*cancel(mL^-1)#

#=# #1.25*mol#

And a #1.25*mol# quantity of sodium chloride has a mass of #1.25*cancel(mol)xx58.44*g*cancel(mol^-1)# #=# #??*g#