Question #959a1

1 Answer
Oct 16, 2016

#-40, -38, -36#

Explanation:

Let #2n# represent the least of the even integers. Then, as the integers are consecutive even integers, we have the next two as #2(n+1)# and #2(n+2)#. Their sum is #-114#, giving us the equation

#2n+2(n+1)+2(n+2) = -114#

#=> 2n+(2n+2)+(2n+4) = -114#

#=> 6n+6 = -114#

#=> 6n = -114-6 = -120#

#=> n = -120/6 = -20#

#=>2n = -40, 2(n+1) = -38, 2(n+2) = -36#

If we check, we find that their sum is #-114# as desired.

Thus, our three consecutive even integers are #-40, -38, -36#.