Can you represent the oxidation of sulfite ion, #SO_3^(2-)#, to give sulfate ion, #SO_4^(2-)#, accompanied by the reduction of #Cu^(2+)# to copper metal?

1 Answer
Oct 18, 2016

Answer:

#SO_3^(2-) + Cu^(2+)+ 2HO^(-) rarr SO_4^(2-) +Cu(s) + H_2O(l)#

Explanation:

When basic conditions are specified, it is normally best to balance the equations in acid, and then modify the final equations.

#"Sulfur (IV+)"# #rarr# #"Sulfur(VI+)":#

#SO_3^(2-) + H_2Orarr SO_4^(2-) +2H^(+) + 2e^(-) #

For basic conditions, add #2xxHO^-# to EACH side #(HO^(-) + H^(+)rarrH_2O)#:

#SO_3^(2-) + 2HO^(-) rarr SO_4^(2-) +H_2O + 2e^(-) #

#"Copper (II+)"# #rarr# #"Copper (0)":#

#Cu^(2+) + 2e^(-) rarr Cu#

You have asked another such question recently. Do you follow the method of doing redox equations?