Question

Question #2a73b

Answer 1

`2x-y=4`.

Explanation:

The Cartesian Eqn. of a plane contining a point `(x_0,y_0,z_0)`

and having its normal vector `(a,b,c)` is given by,

`ax+by+cz=ax_0+by_0+cz_0`.

Accordingly, the desired eqn. of the plane follows :

`2x+(-1)y+0z=2(1)+(-1)(-2)+0(1), i.e.,`

`2x-y=4`.