Question #ae517

1 Answer
sente
Oct 24, 2016

#x=+-2sqrt(7)#

Explanation:

#f(x) = g(x)#

#=> x+5 = 3/(x-5)#

#=> (x+5)(x-5) = 3#

#=> x^2 - 25 = 3#

At this point it would be simplest to just add #25# to both sides and take a square root, but as the question refers to the quadratic formula, we will instead put it in standard form and proceed in that manner.

#=> x^2 - 28 = 0#

#=> 1x^2 + 0x - 28 = 0#

#=> x = (-0+-sqrt(0^2-4(1)(-28)))/(2(1))#

#=(+-4sqrt(7))/2#

#=+-2sqrt(7)#

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