What is the #pH# of a mass of #4.66*mg# of barium hydroxide dissolved in a #1*L# volume of water?

1 Answer
Oct 26, 2016

Answer:

#pH=9.74#

Explanation:

We need to find (i), #[HO^-]# #=# #(2xx4.66xx10^-3g)/(171.34*g*mol^-1)xx1/L# #=# #5.44xx10^-5mol*L^-1#.

And (ii), #pOH# #=# #-log_10[HO^-]# #=# #-log_10(5.44xx10^-5)# #=# #4.26.#

And since (iii) #pH+pOH=14, pH=14-4.26=9.74#.