How is a #5*%v/v# solution of methanol in water prepared?

1 Answer
Nov 2, 2016

Answer:

Take #45*mL# of water and add #5*mL# of methanol. The volumes should be additive and you are left with #5%# methanol, #v/v#.

Explanation:

Of course that method works to a first approximation, and here the dilution is #"volume of solute"/"volume of solution"#. If you want #"mass of solute"/"mass of solution"# you add appropriate masses. The actual concentrations will not be that different.