Question

Question #b05eb

Answer 1

The period is `pi/2`

Explanation:

The expression has the form `2sin(A)cos(A)` where `A=2x`.

`sin(2A)=2sin(A)cos(A)`, so we can rewrite the given expression as `sin(4x)`. The period of a sine function is `P=(2pi)/B`, where `B` is the coefficient of `x`, so the period is `(2pi)/4=pi/2`.