# Question #130a3

Nov 2, 2016

$N a H S {O}_{4}$ produces ${H}^{+}$ ion in its aqueous solution, which combines with $C {O}_{3}^{2} -$ ions (formed on ionisation of $N {a}_{2} C {O}_{3}$) to form ${H}_{2} C {O}_{3}$,an unstable weak acid.This acid readily decomposes to form $C {O}_{2}$ gas.

$2 N a H S {O}_{4} \to 2 N {a}^{+} + 2 {H}^{+} + 2 S {O}_{4}^{\text{2-}}$

$N {a}_{2} C {O}_{3} \to 2 N {a}^{+} + C {O}_{3}^{\text{2-}}$

$C {O}_{3}^{\text{2-}} + 2 {H}^{+} \to {H}_{2} C {O}_{3}$

${H}_{2} C {O}_{3} \to {H}_{2} O + C {O}_{2}$

Equation of the net reaction

$N {a}_{2} C {O}_{3} + 2 N a H S {O}_{4} \to 2 N {a}_{2} S {O}_{4} + {H}_{2} O + C {O}_{2}$