Question

Question #19c82

Answer 1

We need a `14.9*mL` volume of the stock solution.

Explanation:

We require `0.425*Lxx0.210*mol*L^-1=0.08925*mol`.

If there is `6.0*mol*L^-1` stock solution available, we need a volume of `(0.08925*mol)/(6.0*mol*L^-1)xx10^3*mL*L^-1=14.9*mL`. This volume is then diluted to `425*mL`.