# Question #c2483

Nov 3, 2016

$- 2 {x}^{4} \cdot 7 {x}^{4} = - 14 {x}^{8}$

#### Explanation:

Using the commutative and associative properties of multiplication along with the property of exponents that ${x}^{a} \cdot {x}^{b} = {x}^{a + b}$, we have

$- 2 {x}^{4} \cdot 7 {x}^{4} = \left(- 2 \cdot 7\right) \left({x}^{4} \cdot {x}^{4}\right)$

$= \left(- 14\right) \left({x}^{4 + 4}\right)$

$= - 14 {x}^{8}$