# What length of mercury column will a gas at 0.650*atm support?

$1 \cdot a t m$ of pressure will support a column of mercury $760 \cdot m m$ high.
And thus $0.650 \cdot a t m \times 760 \cdot m m \cdot a t {m}^{-} 1$ $=$ ??*mm*Hg.