The de Broglie wavelength of a neutron is 144 pm. What is its velocity ?

1 Answer
Nov 9, 2016

Answer:

#sf(v=2.77xx10^(3)color(white)(x)"m/s")#

Explanation:

#sf(lambda=h/(mv))#

h is the Planck constant = #sf(6.63xx10^(-34)color(white)(x)Js)#

#sf(lambda)# is the wavelength = 144 pm = #sf(1.44xx10^(-10)color(white)(x)m)#

#sf(m=1.67xx10^(-27)color(white)(x)kg)#

#:.##sf(v=h/(mlambda)#

#sf(v=(6.63xx10^(-34))/(1.67xx10^(-27)xx1.44xx10^(-10))color(white)(x)"m/s")#

#sf(v=2.77xx10^(3)color(white)(x)"m/s")#