# What mass of "calcium oxide" results from the decomposition of a 200*g mass of "calcium carbonate"?

##### 1 Answer
Jan 18, 2017

We need (i), a stoichiometrically balanced equation.........

#### Explanation:

$C a C {O}_{3} \left(s\right) + \Delta \rightarrow C a O \left(s\right) + C {O}_{2} \left(g\right) \uparrow$

And thus (ii) moles of limestone are equivalent to the molar quantity of calcium oxide:

$\text{Moles of calcium carbonate}$ $=$ $\frac{200 \cdot g}{100 \cdot g \cdot m o {l}^{-} 1} = 2 \cdot m o l .$

And thus an equivalent quantity of calcium oxide are left, i.e.

2*molxx56*g*mol^-1=??g