Question #55e8d

1 Answer
Nov 11, 2016

Answer:

#PbSO_4+2NH_4OH->Pb(OH)_2(s)+(NH_4)_2SO_4(aq)#

Explanation:

The partial reactions are:
#PbSO_4->Pb^(2+)(aq)+SO_4^(2-)(aq)#
#NH_3+H_2O->NH_4^+(aq) +OH^(-) (aq)# this one times 2
The net reaction is:
#Pb^(2+)(aq)+2OH^(-)(aq) ->Pb(OH)_2(s)#
The #NH_4^+# ions and the #SO_4^(2-)# ion are so-called spectator-ions.