Question #c6f97

1 Answer
Nov 14, 2016

Answer:

# 3.83#[m/s]

Explanation:

The giration radius is given by

#r = l costheta#

The acceleration induced by the rotational movement is

#vec a_r = (omega^2r) hat i = v^2/r hat i#

Considering a noninertial rotating reference frame. In equilibrium, the weigth #-m g hat j# and the centrifugal force #m (v^2/ r) hat i# have null momentum sum concerning the hanging cable fulcrum.

# M_0 = (l sintheta)(m v^2/r)-(l costheta)(m g) = 0#

then

#v=sqrt(cos^2theta/sintheta l g) approx 3.83#[m/s]