An 0.025*mol quantity of hydrogen gas was collected from the reaction of sodium metal with water. What molar quantity of sodium was used?

Nov 19, 2016

$0.05 \cdot m o l \times 22.99 \cdot g \cdot m o {l}^{-} 1$ of sodium metal were reacted.

Explanation:

For the reaction,

$N a \left(s\right) + {H}_{2} O \left(l\right) \rightarrow \frac{1}{2} {H}_{2} \left(g\right) \uparrow + N a O H \left(a q\right)$,

we were given a specified molar quantity of reactant.

For the mass we simply mulitply the number of moles by the molar mass, as given in the intro.