A #5.00*mL# volume of acetic acid required a #45*mL# volume of #0.100*mol*L^-1# #NaOH# for equivalence. What is the concentration of the acetic acid solution?

1 Answer
Nov 20, 2016

Answer:

Approx. #1*mol*L^-1#, with respect to acetic acid.

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#, or #C=n/V#, and clearly #"concentration"# has units of #mol*L^-1#.

We need a reaction:

#H_3C-CO_2H(aq) + NaOH(aq) rarr H_3C-CO_2^(-)""^(+)Na(aq) + H_2O(aq)#

And thus, since
#"moles of sodium hydroxide "-=" moles of acetic acid"#,

there were #45.0*mLxx10^-3L*mL^-1xx0.100*mol*L^-1=# #4.50xx10^-3*mol# of acetic acid in that original #5*mL# volume.

Again, #"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

#=# #(4.50xx10^-3*mol)/(5xx10^-3L)#