# What is the volume occupied by a 91.8*g mass of carbon dioxide that is heated to 517.2*K, and subjected to a pressure of 287*"Torr"?

##### 1 Answer
Jun 20, 2017

$V \cong 235 \cdot L$

#### Explanation:

Given the Ideal Gas equation.....$P V = n R T$

So $V = \frac{n R T}{P}$, and we know that $760 \cdot m m \cdot H g \equiv 1 \cdot a t m$

V=((91.8*g)/(44.01*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx517.2*K)/((287*"Torr")/(760*"Torr"*atm^-1))=??L.

The gas constant conveniently gives us the volume in $\text{litres}$.

Note here that I have (i) converted the pressure in $\text{Torr}$, and (ii) converted the temperature to $\text{degrees Kelvin}$, which are typically used in these reactions.