What is the volume occupied by a #91.8*g# mass of carbon dioxide that is heated to #517.2*K#, and subjected to a pressure of #287*"Torr"#?

1 Answer
Jun 20, 2017

Answer:

#V~=235*L#

Explanation:

Given the Ideal Gas equation.....#PV=nRT#

So #V=(nRT)/P#, and we know that #760*mm*Hg-=1*atm#

#V=((91.8*g)/(44.01*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx517.2*K)/((287*"Torr")/(760*"Torr"*atm^-1))=??L.#

The gas constant conveniently gives us the volume in #"litres"#.

Note here that I have (i) converted the pressure in #"Torr"#, and (ii) converted the temperature to #"degrees Kelvin"#, which are typically used in these reactions.