# Question 787db

Well, for $\text{ethane}$, carbon has an oxidation state of $- I I I$; in ethylamine the ipso carbon also has an oxidation state of $- I$.
For $\text{ethylamine}$, ${H}_{2} N C {H}_{2} C {H}_{3}$ , the methyl carbon again has an oxidation state of $- I I I$, but since the ipso carbon is bound to nitrogen, an atom with greater electronegativity than carbon, the nitrogen gets the electron, i.e. H_2N^(-) +""^+CH_2-R, and so this centre has a formal oxidation state of $- I$:
-CH_2NH_2rarr H_2C^(+) + ""^(-)NH_2rarr2xxH^(+) rarr C^(-I)#